If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2q^2-11q-51=0
a = 2; b = -11; c = -51;
Δ = b2-4ac
Δ = -112-4·2·(-51)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-23}{2*2}=\frac{-12}{4} =-3 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+23}{2*2}=\frac{34}{4} =8+1/2 $
| 492x-3)=5x+7 | | 16–4x2=0 | | 3(x-2)=6(x-2) | | 3(x+2)+2(3x+2)=1 | | 4h+3=-33 | | x/12-1=-3 | | 2(x+3)+3(x+1)=29 | | 8-3x=26-5x | | 9x–12=5x+8 | | 4(x-5)+2(2x-1)=38 | | F^-1(x)=x^2-4x+7 | | x+3=6x−22 | | 60=3(x–2) | | 7h-24=10 | | 7h=24=10 | | 3(3x–2)=48 | | X3-6x2+8x-4=0 | | 2x/5x=30 | | -3x=5x-88 | | -3x=5x+88 | | -5x=-5-4x | | x-12.6=2.1 | | -3x=-72+9x | | 23–a=3a-1 | | 0.25+4m=0.75 | | I4x-3I=x | | 8f+10=58 | | (-5)×(-6)+2x-12=-6 | | X^2-4x-100=0 | | 7b-7=55 | | 5x-8=16–7x | | 8x=-8x+80 |